RE: [xsl] Get value outside of for-each Statement

["john lee" <excel_man@xxxxxxxxxxx>]

Thanks Michael, It works.
Thanks for the help :D



> From: "Michael Kay" <mhk@xxxxxxxxx>
> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Subject: RE: [xsl] Get value outside of for-each Statement
> Date: Thu, 19 Aug 2004 21:48:39 +0100
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>
> >
> > I got a problem with for-each statement. When you are inside
> > a for-each
> > statement, how do you link the value inside the for-each
> > statement with a
> > value that is outside of the element being looped through ?
> >
> > This is the xml:
> >
> > <employee_name>
> > </employee_name>
> > <employee_number>
> > </employee_number>
> >
> > <employee_name>
> > </employee_name>
> > <employee_number>
> > </employee_number>
> >
> > This is the output I want to have:
> > Employee Name: Test1                  Employee Number: 123
> > Employee Name: Test2                  Employee Number: 456
>
> It looks as if the only relationship between an employee name and the
> corresponding number is that they are adjacent, so use
> following-sibling::employee_number[1].
>
> It would be more usual to have an <employee> wrapper element, in which case
> you would do ../employee_number.
>
> Michael Kay
>
> >
> >
> > <xsl:for-each select="employee_name">
> >    <tr>
> >       <td> Employee Name: <xsl:value-of select="employee_name"></td>
> >       <td>Employee Number: ______________________________ </td>
> >   </tr>
> > </xsl:for-each>
> >
> > Any help would be appreciated
> >
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