RE: [xsl] Common Element Solution (XSL 2.0)

Subject: RE: [xsl] Common Element Solution (XSL 2.0)
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Wed, 23 Mar 2005 09:00:33 -0000
> -----Original Message-----
> From: Pawson, David [mailto:David.Pawson@xxxxxxxxxxx] 
> Sent: 23 March 2005 08:24
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>     you want something like
>        count(current-group()/parent::table) = $number-of-tables
>     relying on the fact that "/" eliminates duplicates.
> That last line has me puzzled Mike. Would someone expand please,
> for the uninitiated? 

In the input we have a set of tables each containing zero or more columns,
each column has a name. We want to find the names of the columns that appear
in each table. Group the columns by name; for each group (of columns with
the same name), the column appears in every table if the number of tables
containing a column in that group equals the total number of tables.

Any clearer?

Michael Kay

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