Subject: RE: [xsl] Common Element Solution (XSL 2.0) From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 23 Mar 2005 10:06:46 -0000 |
> <tables> > <table name="table1"> > <column name="col1"/> > <column name="col2"/> > <column name="col3"/> > <column name="col4"/> > </table> > <table name="table2"> > <column name="col1"/> > <column name="col2"/> > <column name="col5"/> > <column name="col6"/> > </table> > > Yes, the basics are clear. Your last line(s) were > you want something like > > count(current-group()/parent::table) = $number-of-tables > > relying on the fact that "/" eliminates duplicates. > > > My question was, how does the '/' eliminate duplicates? > That's the bit I don't understand. If the input is > <table name="table1"> > <column name="col1"/> > <column name="col2"/> > <column name="col3"/> > <column name="col4"/> > </table> > <table name="table2"> > <column name="col1"/> > <column name="col2"/> > <column name="col5"/> > <column name="col5"/> > </table> then when processing col5, count(current-group()) will be 2, but count(current-group()/parent::table) will be 1, because both columns in the group have the same parent element. Michael Kay http://www.saxonica.com/
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