Subject: Re: [xsl] concat all items in a sequence From: andrew welch <andrew.j.welch@xxxxxxxxx> Date: Tue, 30 Aug 2005 15:53:16 +0100 |
On 8/30/05, Michael Kay <mike@xxxxxxxxxxxx> wrote: > > I'm using the following: > > > > contains(elem, val) > > > > It's possible that 'elem' can be a sequence of more than one item. > > > > The way I've code around this is to use string-join with an empty > > string as one of the arguments: > > > > contains(string-join(for $i in elem return $i, ''), val) > > > > Is there a better way? > > 1. The expression > > for $i in elem return $i > > can be rewritten as > > elem > > So you get > > contains(string-join(elem, ''), val) > > 2. Do you want to match substrings that cross item boundaries, e.g. do you > want contains(('red', 'green'), 'edgr') to be true? If so, I don't think you > can do better than the above. If you don't want this, then apply contains to > each string in the sequence separately: > > exists(elem[contains(., val)]) It's the latter, thanks, lots to go on there.
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