Re: [xsl] concat all items in a sequence

Subject: Re: [xsl] concat all items in a sequence
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 31 Aug 2005 10:24:32 +0100
  contains(string-join(for $i in elem return $i, ''), val)

  Is there a better way?
 

you can (always) write 
for $i in elem return $i
as
elem

so if you want to concat you could do


contains(string-join(elem, ''), val)

or (depending on what you want to do if val is a substring of the
concatenation but not of any value, you may want



true()=elem/contains(./val)

David

________________________________________________________________________
This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________

Current Thread