Subject: RE: A theory problem From: Kay Michael <Michael.Kay@xxxxxxx> Date: Fri, 29 Oct 1999 10:05:31 +0100 |
> > [James Clark] > >> A path expression has the property if > >> > >> (a) it doesn't use / and the axis is a forward axis, or > >> > >> (b) it is a / expression, and the left hand operand has the > >> "single-level" property and the right hand operand has the > >> "stays-in-subtree" property. > > [Michael Kay] > >This is nice and clean, but it doesn't seem to catch > >child::A/child::B/child::C. > > Do you mean as a select or as a match pattern? As a select, > child::A is > single-level and child::B has stays-in-subtree; taken together, > child::A/child::B is single-level and child::C has stays-in-subtree. > We're talking about expressions not patterns, since document order is irrelevant in patterns. James' definition of "single-level" was that a set of nodes was single level if they all had the same parent; therefore child::A/child::B is not single level. This is why I was trying to use a more general concept of "peer" nodes. Mike XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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