Subject: Re: [xsl] How to specify a path to a node in a nodeset using a variable From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Wed, 14 Mar 2001 08:56:12 +0000 |
Hi Shakeel, > I tried it and it works!!! But it is a mystery what exactly is > saxon:evaluate() doing? saxon:evaluate() takes a string that is an XPath expression and evaluates it, returning the result of the expression. > It receives the following argument $container//account/person/@name > because of the concat function. > > concat('$container/', $path) where $path is /account/person/@name > > Is $container//account/person/@name a valid XPath expression? Yes. It says: get all the nodes in the $container variable get all their account element descendants get all their person element children get all their name attributes and return that node set > I tried looking up the documentation for the saxon:evaluate and > xalan:evaluate() but I couldnt answer the question. If you want to learn about XPath expressions, you should have a look at the XPath Recommendation at http://www.w3.org/TR/xpath. Or one of the online tutorials about them. > Do I need an extra slash between $container and the $path? It depends what you want. If the nodes in the $container variable are the parents of the account elements, then no, you shouldn't have the extra slash. If the nodes in the $container variable are just ancestors of the account elements, then yes, you do. I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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