Re: [xsl] Xslt string Operation

["Mailing Lists Mail daktapaal@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

I meant
<xsl:variable name="OutFileName" select=" substring-before($fileHref,
tokenize($fileHref,'/')[last()] ) || $outDir || '/' ||   substring-before(
tokenize($fileHref,'/')[last()] ,'.xml') || '-Formatted.xml'"/>

I can also take tokenize($fileHref,'/')[last()] in a variable and use it in
the string operation above. But is there a better way ?

On Aug 24, 2016 12:16 PM, "Mailing Lists Mail daktapaal@xxxxxxxxx" <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Dear all,
> I have the following two params
> <xsl:param name = bfileHrefb select = b
bP:/developers/perf/bigPayload.xmlb b/>
> <xsl:param name="outDir" select="'outDir'"/>
>
>   I want OutFileName to be :
bP:/developers/perf/outDir/bigPayload-Formatted.xmlb
>
> Is there a better way to do this than what I did?
> <xsl:variable name="OutFileName" select=" substring-before($fileHref,
tokenize($fileHref,'/')[last() -1 ] ) || $outDir || '/' ||
substring-before( tokenize($fileHref,'/')[last()] ,'.xml') ||
'-Formatted.xml'"/>
>
> thanks.
> Dt
>
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