Re: [xsl] Xslt string Operation

Subject: Re: [xsl] Xslt string Operation
From: "Heiko Niemann kontakt@xxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Wed, 24 Aug 2016 21:59:34 -0000
Hi,

this also returns the expected result in your sample.

replace($fileHref, '(^.*/)([^.]*)(.*$)', concat('$1', $outDir,
'/$2-Formatted$3'))

It might be better in terms of shorter or easier to read...

Heiko



> So,
> The params had default values and that is exactly the way i am expecting
> the caller to send these params. With fwd slashes, with .xml as file name
> extention and always windows file name.. that is kind of why i put the
> value in the param to give an example.
> What i did works, but wanted to know if there was a better way.
> Dak.
>
> On Aug 24, 2016 4:13 PM, "Michael Kay mike@xxxxxxxxxxxx" <
> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
>> Actually, you want OutFileName to be a function of fileHref and outDir,
>> and you are asking us to work out what that function does from one
>> example
>> of its input and output. To do this properly we need to know what the
>> possible range of values of fileHref and outDir is: for example, is
>> fileHref always a Windows filename using forwards slashes to separate
>> the
>> parts of the path? Will it always end in ".xml"? Or since it's a param,
>> might someone pass in a filename using backslashes, with no file
>> extension?
>>
>> I would encourage you to use URIs rather than filenames. You could then
>> use the resolve-uri() function for at least part of the task.
>>
>> Michael Kay
>> Saxonica
>>
>> On 24 Aug 2016, at 17:16, Mailing Lists Mail daktapaal@xxxxxxxxx <
>> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>>
>> Dear all,
>> I have the following two params
>> <xsl:param name = bfileHrefb select = b
>> bP:/developers/perf/bigPayload.xmlb
>> b/>
>> <xsl:param name="outDir" select="'outDir'"/>
>>
>>   I want OutFileName to be : bP:/developers/perf/outDir/
>> bigPayload-Formatted.xmlb
>>
>> Is there a better way to do this than what I did?
>> <xsl:variable name="OutFileName" select=" substring-before($fileHref,
>> tokenize($fileHref,'/')[last() -1 ] ) || $outDir || '/' ||
>> substring-before( tokenize($fileHref,'/')[last()] ,'.xml') ||
>> '-Formatted.xml'"/>
>>
>> thanks.
>> Dt
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