RE: [xsl] Shorthand.

["Angela Williams" <Angela.Williams@xxxxxxxxxxxxxxxxxx>]

I just noticed the OP is selecting the string 'x' and the string 'y' and
has the param and with-param backwards in the example. You call a
template *with* a param and the named template *has* a param.

I'm sure this was just a typo in trying to provide an example, but could
give a newbie some debugging frustration if not...


Thanks!
Angela

-----Original Message-----
From: Andrew Welch [mailto:andrew.j.welch@xxxxxxxxx]
Sent: Wednesday, July 25, 2007 11:58 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Shorthand.

On 7/25/07, Steve <subsume@xxxxxxxxx> wrote:
> Hey there, I have a template for creating ajax links:
>
> <xsl:template name="a">
>         <xsl:with-param name="href" />
>         <xsl:with-param name="text" />
>         <a href="{$href}" onClick="showData('{$href}');return
> false;"><xsl:value-of select="$text" /></a> </xsl:template>
>
> is there some shorter way to use this (XSL 1.0) template than...
>
> <xsl:call-template name="a">
>    <xs:param name="href" select="'x'"/>
>    <xs:param name="text" select="'y'"/> </xsl:call-template>

It depends...

If x and y are selected from the current node, then you can just go:

<xsl:call-template name="a"/>

and

<xsl:template name="a">
  <a href="{@x}" .....>
    <xsl:value-of select="y"/>
  </a>
</xsl:template>

...as the current node is the same within the named template as it is
when you call the named template.

(if not then that's the correct way.)

cheers
andrew
--
http://andrewjwelch.com