Re: [xsl] Shorthand.

[Steve <subsume@xxxxxxxxx>]

Typo =)

On 7/25/07, Angela Williams <Angela.Williams@xxxxxxxxxxxxxxxxxx> wrote:
> I just noticed the OP is selecting the string 'x' and the string 'y' and
> has the param and with-param backwards in the example. You call a
> template *with* a param and the named template *has* a param.
>
> I'm sure this was just a typo in trying to provide an example, but could
> give a newbie some debugging frustration if not...
>
>
> Thanks!
> Angela
>
> -----Original Message-----
> From: Andrew Welch [mailto:andrew.j.welch@xxxxxxxxx]
> Sent: Wednesday, July 25, 2007 11:58 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Shorthand.
>
> On 7/25/07, Steve <subsume@xxxxxxxxx> wrote:
> > Hey there, I have a template for creating ajax links:
> >
> > <xsl:template name="a">
> >         <xsl:with-param name="href" />
> >         <xsl:with-param name="text" />
> >         <a href="{$href}" onClick="showData('{$href}');return
> > false;"><xsl:value-of select="$text" /></a> </xsl:template>
> >
> > is there some shorter way to use this (XSL 1.0) template than...
> >
> > <xsl:call-template name="a">
> >    <xs:param name="href" select="'x'"/>
> >    <xs:param name="text" select="'y'"/> </xsl:call-template>
>
> It depends...
>
> If x and y are selected from the current node, then you can just go:
>
> <xsl:call-template name="a"/>
>
> and
>
> <xsl:template name="a">
>   <a href="{@x}" .....>
>     <xsl:value-of select="y"/>
>   </a>
> </xsl:template>
>
> ...as the current node is the same within the named template as it is
> when you call the named template.
>
> (if not then that's the correct way.)
>
> cheers
> andrew
> --
> http://andrewjwelch.com