Re: [xsl] Count items in a key ?

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

On Wed, Oct 13, 2010 at 8:23 AM, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote:
> New XSLT 2.1 feature? :)


Could be something as:

      keys(keyname as xs:string) as item()*

and an additional overload:

      keys(keyname as xs:string, document as document-node()) as item()*



--
Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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Never fight an inanimate object
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You've achieved success in your field when you don't know whether what
you're doing is work or play





>
> ~ Scott
>
>
> -----Original Message-----
> From: Michael Kay [mailto:mike@xxxxxxxxxxxx]
> Sent: Wednesday, October 13, 2010 10:15 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Count items in a key ?
>
> B On 13/10/2010 3:23 PM, Fabien Tillier wrote:
>> Hi List.
>> I would like to know if it is possible to get all "key" item from an
>> xsl:key ?
>> I mean:
>> when you define a key, say:
>> B  B  B  <xsl:key name="mykey" match="NODE" use="@id"/>
>>
>> You can retrieve all NODE nodes with a given @id attribute.
>> But is it possible to retrieve all distinct @id values from the key ?
>> (I know it is possible to get them from the XML file, but wouldn't it be
>> faster to get what is already retrieved ?)
>>
>>
> No, this isn't available. I don't think there's any good reason for not
> providing it.
>
> Michael Kay
> Saxonica