Subject: Re: [xsl] Count items in a key ? From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Wed, 13 Oct 2010 11:50:59 -0700 |
On Wed, Oct 13, 2010 at 11:25 AM, Olivier Jeulin <olivier.jeulin@xxxxxxxxx> wrote: > Le 13/10/2010 19:50, Dimitre Novatchev a C)crit : >> >> On Wed, Oct 13, 2010 at 8:23 AM, Scott Trenda<Scott.Trenda@xxxxxxxx> >> B wrote: >>> >>> New XSLT 2.1 feature? :) >> >> >> Could be something as: >> >> B B B keys(keyname as xs:string) as item()* >> >> and an additional overload: >> >> B B B keys(keyname as xs:string, document as document-node()) as item()* > > Yes, it looks fine. But keys are atomized, so shouldn't keys() return > xs:anyType* instead of item()* ? Did you mean xs:anyAtomicType* ? Yes, this is precise. -- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- Never fight an inanimate object ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play
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