Re: [xsl] Count items in a key ?

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2010-10-13 23:02 +0200, Olivier Jeulin wrote:
> Le 13/10/2010 20:50, Dimitre Novatchev a C)crit :
> > On Wed, Oct 13, 2010 at 11:25 AM, Olivier Jeulin
> > <olivier.jeulin@xxxxxxxxx>  wrote:
> > > Le 13/10/2010 19:50, Dimitre Novatchev a C)crit :
> > > > On Wed, Oct 13, 2010 at 8:23 AM, Scott Trenda<Scott.Trenda@xxxxxxxx>
> > > >   wrote:
> > > > > New XSLT 2.1 feature? :)
> > > >
> > > >
> > > > Could be something as:
> > > >
> > > >        keys(keyname as xs:string) as item()*
> > > >
> > > > and an additional overload:
> > > >
> > > >        keys(keyname as xs:string, document as document-node()) as
item()*
> > > Yes, it looks fine. But keys are atomized, so shouldn't keys() return
> > > xs:anyType* instead of item()* ?
> >
> >
> > Did you mean xs:anyAtomicType*   ? Yes, this is precise.
>
> According to
> http://www.w3.org/TR/xpath-datamodel/#types-hierarchy
> xs:anyType seemed to be the most generic type,
> but I'm not an xpath/schema datatype guru ;)

But since the lookup value cannot be a node, I
think Dimitre's xs:anyAtomicType* is more appropriate than xs:anyType.

I hope this helps.

. . . . . . . . . . Ken

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