Re: [xsl] How to count the distinct values where elements with missing child are counted as one of the distinct values?

["Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

> Use count(distinct-values(/test/row/string(transition)))

I would use the more obvious and self-explanatory:

let $test := /test/row
  return
     count(distinct-values($test/transition)) + 1[$test[not(transition)]]

If this XPath evaluation is initiated from an XSLT transformation and XSLT
1.0 compatibility set to true (Specifying version = "1.0" but using an XSLT
2.0 or later processor), one can use even:

 count(distinct-values(/test/row/transition)) +
boolean(/test/row[not(transition)])


Thanks,
Dimitre

On Thu, May 26, 2022 at 7:33 AM Michael Kay mike@xxxxxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> Use count(distinct-values(/test/row/string(transition)))
>
> string() applied to an empty sequence returns the zero-length string,
> whereas atomization applied to an empty sequence returns an empty sequence.
>
> Michael Kay
> Saxonica
>
> > On 26 May 2022, at 15:08, Roger L Costello costello@xxxxxxxxx <
> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> >
> > Hi Folks,
> >
> > The following XML document has two row elements with no transition
> element and two row elements with a transition element :
> >
> > <test>
> >    <row>
> >    </row>
> >    <row>
> >    </row>
> >    <row>
> >        <transition>ABC</transition>
> >    </row>
> >    <row>
> >        <transition>DEF</transition>
> >    </row>
> > </test>
> >
> > I want a count of the number of distinct transition values, where row
> elements with no transition element are counted as 1.
> >
> > So for the above XML document the count should return 3.
> >
> > This XPath seems to work:
> >
> > count(distinct-values(/test/row/transition)) +
> count(/test/row[not(transition)][1])
> >
> > But I am wondering if there is a better (simpler, less kludgy) XPath
> expression?
> >
> > /Roger
> >
> >
> 
>
>

-- 
Cheers,
Dimitre Novatchev
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