Re: [xsl] How to count the distinct values where elements with missing child are counted as one of the distinct values?

Subject: Re: [xsl] How to count the distinct values where elements with missing child are counted as one of the distinct values?
From: "Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Fri, 27 May 2022 20:24:31 -0000
>  Actually, that's not equivalent. My solution (using string()) treats an
empty transition element and an absent transition element as equivalent;
DImitre's solution treats them as distinct.

This is clearly what Roger (the OP) wanted. He wrote:

> I want a count of the number of distinct transition values, where row
elements with no transition element are counted as 1.

On Fri, May 27, 2022 at 9:05 AM Michael Kay mike@xxxxxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>
> > Use count(distinct-values(/test/row/string(transition)))
>
> I would use the more obvious and self-explanatory:
>
> let $test := /test/row
>   return
>      count(distinct-values($test/transition)) + 1[$test[not(transition)]]
>
>
> Actually, that's not equivalent. My solution (using string()) treats an
> empty transition element and an absent transition element as equivalent;
> DImitre's solution treats them as distinct.
>
> Michael Kay
> Saxonica
>
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>


-- 
Cheers,
Dimitre Novatchev
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