Dennis wrote:
>Would playerMotion here be the "delay" frames I have set up for the
>players (i.e. 4, 3, 2, and 1)?
No, playerMotion would contain "fractional delay frames".
Example: (SBC #$60)
frame playerMotion C
- $00 -
0 $a0 0
1 $40 1
2 $e0 0
3 $80 1
4 $20 1
5 $c0 0
6 $60 1
7 $00 1
The carry is clear in 3 out of 8 frames, so your resulting speed is
3/8 = ($60/$100). Fractional!
Other values: $aa -> ~2/3, $80 -> 1/2, $55 -> ~1/3, $40 = 1/4, ...
(but you can use *any* values you like here, e.g. $ca -> ~0.79)
Note that playerMotion is only changed here and *not* reseted when
moving!
>As a matter of fact, where did you get the numbers for the first
>routine? Is there a formula you're using that I'm missing?
I think by now you should have got the answer already. Else it's my
fault and I should learn to explain myself better. ;-)
>you clear the carry bit instead of setting it so a bcc would move the
>player for the given frame.
I am using CLC to be able to subtract $100 (by using $ff) so that the
carry after the subtraction is always cleared and I get maximum speed
then (SBC M: A = A - M - 1 + C). Therefore I am reducing all subtract
values by 1.
BTW: You can use ADC (and SEC) instead. That's maybe a bit easier to
understand.
>$04 - $3F = $C5 -> carry set, right?
>$C5 - $3F = $86 -> carry cleared???
No, it's exactly the other way around. The carry is cleared when the
subtraction "crosses" 0.
>My only question for this is where do you come up with the number 30?
>I understand you get 36 from 30*6/5.
Why 30? Hm, it's 5*6. :-)
But you can use any higher value here as long as the results don't get
larger than $ff. And the conversion to PAL works best when it can be
divided by 5.
Have fun!
Thomas
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