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Subject: Re: [xsl] Ordered union of sequences From: "Imsieke, Gerrit, le-tex" <gerrit.imsieke@xxxxxxxxx> Date: Thu, 08 Apr 2010 18:22:20 +0200 |
<xsl:function name="my:sortkey" as="xs:integer">
<xsl:param name="input" as="element(*)" />
<xsl:param name="seen" as="xs:string*" />
<xsl:if test="name($input) = $seen">
<xsl:message terminate="yes">Element
<xsl:value-of select="name($input)"/>
doesn't seem to occur at a deterministic
position.
</xsl:message>
</xsl:if>
<xsl:variable
name="preceding-siblings"
select="$input/../../seq/*[
name() = name($input)
]/preceding-sibling::*[1]"
as="element(*)*" />
<xsl:variable name="seen" select="($seen, name($input))" />
<xsl:sequence select="(
max(
for $ps in $preceding-siblings
return my:sortkey($ps, $seen)
) + 1,
1
)[1]"/>
<!-- short form of if(not(empty($preceding-siblings))) -->
</xsl:function><xsl:function name="my:sortkey" as="xs:integer"> <xsl:param name="input" as="element(*)" /> <xsl:param name="previously-seen" as="xs:string*" /> <xsl:if test="name($input) = $previously-seen"> <xsl:message terminate="yes">Element <xsl:value-of select="name($input)"/> doesn't seem to occur at an deterministic position. </xsl:message> </xsl:if> <xsl:variable name="preceding-siblings" select="$input/../../seq/*[name() = name($input)]/preceding-sibling::*[1]" as="element(*)*" /> <xsl:variable name="seen" select="distinct-values(($previously-seen, name($input)))" /> <xsl:sequence select="(max(for $ps in $preceding-siblings return my:sortkey($ps, $seen)) + 1, 1)[1]"/> </xsl:function>
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