Re: [xsl] Sorting by child element count

Subject: Re: [xsl] Sorting by child element count
From: "Mark" <mark@xxxxxxxxxxxx>
Date: Wed, 29 Dec 2010 07:39:12 -0800
Hi Michel,
Good idea if there is no better way. But since there are 400 <Item> elements in the list and hand counting is subject to error, I was hoping to automate the task. However, I can use this solution if no automated method is forthcoming.

-----Original Message----- From: Michel Hendriksen
Sent: Wednesday, December 29, 2010 7:36 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Sorting by child element count

Maybe not the best way but you could copy/preprocess the Item elements
and add an atribute with the number of Data elements. Then sort on the


On Wed, Dec 29, 2010 at 4:21 PM, Mark <mark@xxxxxxxxxxxx> wrote:
Happy new year! Thanks for all the help this list has given me over the past
two years. My question:

I have an XML document that looks like the listing below. I want to sort the
<List> by <Item> so that all the <Items> with one <Data> element are
followed by all the <Items> with two <Data> elements, and so on, until the
last <Items> in the output list have the most <Data> elements. The <Data>
elements have to remain inside their original parent <Item>.

No clue how to begin. Can you point me in the right direction?


          ... <!possibly 1 to 10 or so <Data> elements in each parent
<Item> element.
   ... <!400 <Item> elements in the <List> >

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