Re: [xsl] Sorting by child element count

Subject: Re: [xsl] Sorting by child element count
From: Michel Hendriksen <michel.hendriksen@xxxxxxxxx>
Date: Wed, 29 Dec 2010 16:40:24 +0100
Not hand counting, use stylesheet to do it for you. with xsl:copy p.e.

On Wed, Dec 29, 2010 at 4:39 PM, Mark <mark@xxxxxxxxxxxx> wrote:
> Hi Michel,
> Good idea if there is no better way. But since there are 400 <Item>
> in the list and hand counting is subject to error, I was hoping to automate
> the task. However, I can use this solution if no automated method is
> forthcoming.
> Regards,
> Mark
> -----Original Message----- From: Michel Hendriksen
> Sent: Wednesday, December 29, 2010 7:36 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Sorting by child element count
> Maybe not the best way but you could copy/preprocess the Item elements
> and add an atribute with the number of Data elements. Then sort on the
> attribute.
> Michel
> On Wed, Dec 29, 2010 at 4:21 PM, Mark <mark@xxxxxxxxxxxx> wrote:
>> Happy new year! Thanks for all the help this list has given me over the
>> past
>> two years. My question:
>> I have an XML document that looks like the listing below. I want to sort
>> the
>> <List> by <Item> so that all the <Items> with one <Data> element are
>> followed by all the <Items> with two <Data> elements, and so on, until the
>> last <Items> in the output list have the most <Data> elements. The <Data>
>> elements have to remain inside their original parent <Item>.
>> No clue how to begin. Can you point me in the right direction?
>> Thanks,
>> Mark
>> <List>
>>  <Item>
>>      <Data>...</Data>
>>          ... <!possibly 1 to 10 or so <Data> elements in each parent
>> <Item> element.
>>      <Data>...</Data>
>>  </Item>
>>   ... <!400 <Item> elements in the <List> >
>> </List>

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