Subject: Re: [xsl] Sorting by child element count From: Michel Hendriksen <michel.hendriksen@xxxxxxxxx> Date: Wed, 29 Dec 2010 16:40:24 +0100 |
Not hand counting, use stylesheet to do it for you. with xsl:copy p.e. On Wed, Dec 29, 2010 at 4:39 PM, Mark <mark@xxxxxxxxxxxx> wrote: > Hi Michel, > Good idea if there is no better way. But since there are 400 <Item> elements > in the list and hand counting is subject to error, I was hoping to automate > the task. However, I can use this solution if no automated method is > forthcoming. > Regards, > Mark > > -----Original Message----- From: Michel Hendriksen > Sent: Wednesday, December 29, 2010 7:36 AM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Sorting by child element count > > Maybe not the best way but you could copy/preprocess the Item elements > and add an atribute with the number of Data elements. Then sort on the > attribute. > > Michel > > On Wed, Dec 29, 2010 at 4:21 PM, Mark <mark@xxxxxxxxxxxx> wrote: >> >> Happy new year! Thanks for all the help this list has given me over the >> past >> two years. My question: >> >> I have an XML document that looks like the listing below. I want to sort >> the >> <List> by <Item> so that all the <Items> with one <Data> element are >> followed by all the <Items> with two <Data> elements, and so on, until the >> last <Items> in the output list have the most <Data> elements. The <Data> >> elements have to remain inside their original parent <Item>. >> >> No clue how to begin. Can you point me in the right direction? >> >> Thanks, >> Mark >> >> <List> >> <Item> >> <Data>...</Data> >> ... <!possibly 1 to 10 or so <Data> elements in each parent >> <Item> element. >> <Data>...</Data> >> </Item> >> ... <!400 <Item> elements in the <List> > >> </List>
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