Re: [xsl] Sorting by child element count

Subject: Re: [xsl] Sorting by child element count
From: "Mark" <mark@xxxxxxxxxxxx>
Date: Wed, 29 Dec 2010 07:46:59 -0800
Thanks, Ken -- worked like a charm.

-----Original Message----- From: G. Ken Holman
Sent: Wednesday, December 29, 2010 7:39 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Sorting by child element count

The sort criteria can be any calculation, it does
not have to be performed on data found in the
instance, therefore the criteria is simply expressed as:

  <xsl:apply-templates select="Item">
    <xsl:sort select="count(Data)" data-type="number"/>

I hope this helps.

. . . . . . . . . . Ken

At 2010-12-29 07:21 -0800, Mark wrote:
Happy new year! Thanks for all the help this list has given me over the past two years. My question:

I have an XML document that looks like the listing below. I want to sort the <List> by <Item> so that all the <Items> with one <Data> element are followed by all the <Items> with two <Data> elements, and so on, until the last <Items> in the output list have the most <Data> elements. The <Data> elements have to remain inside their original parent <Item>.

No clue how to begin. Can you point me in the right direction?


... <!bpossibly 1 to 10 or so <Data> elements in each parent <Item> element.
... <!b400 <Item> elements in the <List> B->

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