Subject: Re: [xsl] Sorting by child element count|
From: "Mark" <mark@xxxxxxxxxxxx>
Date: Wed, 29 Dec 2010 07:46:59 -0800
Thanks, Ken -- worked like a charm. Mark
The sort criteria can be any calculation, it does not have to be performed on data found in the instance, therefore the criteria is simply expressed as:
<xsl:apply-templates select="Item"> <xsl:sort select="count(Data)" data-type="number"/> </xsl:apply-templates>
Happy new year! Thanks for all the help this list has given me over the past two years. My question:
I have an XML document that looks like the listing below. I want to sort the <List> by <Item> so that all the <Items> with one <Data> element are followed by all the <Items> with two <Data> elements, and so on, until the last <Items> in the output list have the most <Data> elements. The <Data> elements have to remain inside their original parent <Item>.
No clue how to begin. Can you point me in the right direction?
... <!bpossibly 1 to 10 or so <Data> elements in each parent <Item> element.
... <!b400 <Item> elements in the <List> B->
-- Contact us for world-wide XML consulting & instructor-led training Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Legal business disclaimers: http://www.CraneSoftwrights.com/legal