Subject: Re: [xsl] Sorting by child element count|
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 29 Dec 2010 15:43:04 +0000
Happy new year! Thanks for all the help this list has given me over the past two years. My question:
I have an XML document that looks like the listing below. I want to sort the <List> by <Item> so that all the <Items> with one <Data> element are followed by all the <Items> with two <Data> elements, and so on, until the last <Items> in the output list have the most <Data> elements. The <Data> elements have to remain inside their original parent <Item>.
No clue how to begin. Can you point me in the right direction?
<List> <Item> <Data>...</Data> ... <!bpossibly 1 to 10 or so <Data> elements in each parent <Item> element. <Data>...</Data> </Item> ... <!b400 <Item> elements in the <List> b> </List>
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xsl;for-each select=Item xsl:sort select="count(Data)"