Re: [xsl] Sorting by child element count

Subject: Re: [xsl] Sorting by child element count
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Wed, 29 Dec 2010 10:39:15 -0500
The sort criteria can be any calculation, it does
not have to be performed on data found in the
instance, therefore the criteria is simply expressed as:

  <xsl:apply-templates select="Item">
    <xsl:sort select="count(Data)" data-type="number"/>

I hope this helps.

. . . . . . . . . . Ken

At 2010-12-29 07:21 -0800, Mark wrote:
Happy new year! Thanks for all the help this
list has given me over the past two years. My question:

I have an XML document that looks like the
listing below. I want to sort the <List> by
<Item> so that all the <Items> with one <Data>
element are followed by all the <Items> with two
<Data> elements, and so on, until the last
<Items> in the output list have the most <Data>
elements. The <Data> elements have to remain
inside their original parent <Item>.

No clue how to begin. Can you point me in the right direction?


           ... <!possibly 1 to 10 or so <Data>
elements in each parent <Item> element.
    ... <!400 <Item> elements in the <List> ->

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